Perimeter Calculator is a free online tool that displays the perimeter of the rectangle. BYJU’S online perimeter calculator tool makes the calculation faster, and it displays the perimeter value in a fraction of seconds. Show How to Use the Perimeter Calculator?The procedure to use the perimeter calculator is as follows: What is Meant by the Perimeter?In mathematics, the perimeter is defined as the length of the boundary of any two-dimensional shape. The perimeter can be found for different geometric shapes such as triangle, square, rectangle, pentagon, hexagon, heptagon, octagon, etc. The perimeter of the
rectangle is the sum of the sides of the rectangle. Since the opposite sides of the rectangle are of equal length, the perimeter of the rectangle is given as Here, the list of perimeter calculators for various geometrical shapes is provided to make your calculations easier. The formula of perimeter and area of rectangle are explained step-by-step with solved examples. If l denotes the length and b denotes the breadth of the rectangle, then the  ●
Perimeter of the rectangle = 2(l + b) units ● Length of the rectangle = \(\frac{P}{2}\) - b units ● Breadth of the rectangle = \(\frac{P}{2}\) - l units ● Area of the rectangle = l × b sq. units. ● Length of the rectangle = \(\frac{A}{b}\) units . ● Breadth of the rectangle = \(\frac{A}{l}\) units ● Diagonal of the rectangle = \(\sqrt{l^{2} + b^{2}}\) units Let us consider a rectangle of length 'a' units and breadth 'b' units. Therefore, perimeter of the rectangle ABCD = (AB + BC + CD + DA) units = (a + b + a + b) units = (2a + 2b) units = 2 (a + b) units Therefore, perimeter of the rectangle = 2 (length + breadth) units We know that the area of the rectangle is given by Area = length × breadth A = a × b square units ⇒ a = \(\frac{A}{b}\), i.e., length of the rectangle = \(\frac{Area}{breadth}\) And b = \(\frac{A}{a}\), i.e., breadth of the rectangle = \(\frac{Area}{length}\) Worked-out
problems on Perimeter and Area of Rectangle: 1. Find the perimeter and area of the rectangle of length 17 cm and breadth 13 cm. Solution: Given: length = 17 cm, breadth = 13 cm Perimeter of rectangle = 2 (length + breadth) = 2 (17 + 13) cm = 2 × 30 cm = 60 cm We know that the area of rectangle = length × breadth
= (17 × 13) cm\(^{2}\) 2. Find the breadth of the rectangular plot of land whose area is 660 m2 and whose length is 33 m. Find its perimeter. Solution: We know that the breadth of the rectangular plot = \(\frac{Area}{length}\)
= \(\frac{660m^{2}}{33 m}\) = 20 m Therefore, the perimeter of the rectangular plot = 2
(length + breadth) = 2(33 + 20) m
= 2 × 53 m = 106 m 3. Find the area of the rectangle if its perimeter is 48 cm and its breadth
is 6 cm. Here, P = 48 cm; b = 6 cm Therefore, 48 = 2 (l + 6) ⇒ \(\frac{48}{2}\) = l + 6 ⇒ 24 = l + 6 ⇒ 24 - 6 = l ⇒ 18 = l Therefore, length = 18 cm Now, area of rectangle = l × b = 18 × 6 cm\(^{2}\) = 108 cm\(^{2}\)
4. Find the breadth and perimeter of the rectangle if its area is 96 cm\(^{2}\) Solution: Given, A = 96 cm\(^{2}\) and l = 12 cm A = l × b Therefore, 96 = 12 × b ⇒ \(\frac{96}{12}\) = b ⇒ b = 8 cm Now, P = 2 (l + b) = 2 (12 + 8) = 2 × 20 5. The length and breadth of a rectangular courtyard is 75 m and 32 m. Find the cost of leveling it at the rate of $3 per m2. Also, find the distance covered by a boy to take 4 rounds of the courtyard. Solution: Length of the courtyard = 75 m Breadth of the courtyard = 32 m Perimeter of the courtyard = 2 (75 + 32) m
= 2 × 107 m = 214 m Distance covered by the boy in taking 4 rounds = 4 × perimeter of courtyard
= 4 × 214 = 856 m We know that area of the courtyard =
length × breadth = 75 × 32 m\(^{2}\) = 2400 m\(^{2}\) For 1 m\(^{2}\), the cost of levelling = $3 For 2400 m\(^{2}\), the cost of levelling = $3 × 2400
= $7200 Solved examples on Perimeter and Area of Rectangle: 6. A floor of the room 8 m long and 6 m wide is to be covered by square tiles. If each square tile is 0.8 m, find the number of tiles required to cover the floor. Also, find the cost of tiling at the rate of $7 per tile. Solution: Length of the room = 8 m Breadth of the room = 6 m Area of the room = 8 × 6 m\(^{2}\) {Area of room = Area of tiles that are put on the floor of the room.} = 48 m\(^{2}\) Area of one square tile = 0.8 × 0.8 m\(^{2}\) = 0.64 m\(^{2}\) Number of tiles required = \(\frac{Area of floor}{Area of tiles}\) = \(\frac{48}{0.64}\)
= \(\frac{48 × 100}{64}\) = 75 tiles For 1 tile, the cost of tiling is $7 For 7 tiles, the cost of tiling is $(7 × 75) = $525 7. The breadth of the rectangle is 8 cm and A its diagonal is 17 cm. Find the area of the rectangle and its perimeter. Solution: Using Pythagoras theorem, BD\(^{2}\) = DC\(^{2}\) + BC\(^{2}\) ⇒ 172 = DC\(^{2}\) + 8\(^{2}\) ⇒ 289 - 64 = DC\(^{2}\) ⇒ 225 = DC\(^{2}\) ⇒ 15 = DC Therefore, length of rectangle = 15 cm So, area of rectangle = l × b = 15 × 8 cm\(^{2}\) = 120 cm\(^{2}\) Also, perimeter of rectangle = 2 (15 + 8) cm
= 2 × 23 cm 8. The length and breadth of the rectangle park are in the ratio 5 : 4 and its area is 2420 m2, find the cost of fencing the park at the rate of $10 per metre. Solution: Let the common ratio b x, then length of rectangular park = 5x Breadth of rectangular park = 4x Area of
rectangular park = 5x × 4x = 20x\(^{2}\) According to the question, 20x\(^{2}\) = 2420 ⇒ x\(^{2}\) = \(\frac{2420}{20}\) ⇒ x\(^{2}\) = 121 ⇒ x = 11 Therefore, 5x = 5 × 11 = 55 and 4x = 4 × 11 = 44 So, the perimeter of the rectangular park = 2 (l + b) = 2 (55 + 44)
= 2 × 99 = 198 cm For 1 m, the cost of
fencing = $10 For 198 m, the cost of fencing = $198 × 10 9. How many envelopes can be made out of a sheet of paper 100 cm by 75 cm, supposing 1 envelope requires 20 cm by 5 cm piece of paper? Solution: Area of the sheet = 100 × 75 cm\(^{2}\) = 7500 cm\(^{2}\) Area of envelope = 20 × 5 cm = 100 cm\(^{2}\) Number of envelopes that
can be made = \(\frac{Area of sheet}{Area of envelope}\) = \(\frac{7500}{100}\) 10. A wire in the shape of rectangle of length 25 cm and breadth 17 cm is rebent to form a square. What will be the measure of each side? Solution: Perimeter of rectangle = 2 (25 + 17) cm = 2 × 42 = 84 cm Perimeter of square of side x cm = 4x Therefore,
perimeter of rectangle = Perimeter of Square 84 cm = 4x ⇒ x = 21 Therefore, each side of square = 21 cm These are the detailed step-by-step explanation with the formula of perimeter and area of rectangle. ● Mensuration Area and Perimeter Perimeter and Area of Rectangle Perimeter and Area of Square Area of the Path Area and Perimeter of the Triangle Area and Perimeter of the Parallelogram Area and Perimeter of Rhombus Area of Trapezium Circumference and Area of Circle Units of Area Conversion Practice Test on Area and Perimeter of Rectangle Practice Test on Area and Perimeter of Square ● Mensuration - Worksheets Worksheet on Area and Perimeter of Rectangles Worksheet on Area and Perimeter of Squares Worksheet on Area of the Path Worksheet on Circumference and Area of Circle Worksheet on Area and Perimeter of Triangle Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need. Can you find area of rectangle with perimeter?The perimeter P of a rectangle is given by the formula, P=2l+2w , where l is the length and w is the width of the rectangle. The area A of a rectangle is given by the formula, A=lw , where l is the length and w is the width.
Do all rectangles with the same area have the same perimeter?We found out that rectangles that have the same area don't necessarily have the same perimeter.
What is the area of the rectangle calculator?As we know the formula for the area of a rectangle A = a × b , let's show with an example how you can calculate that property: Choose the length of the rectangle – for example, a = 5 cm . Decide on the rectangle's width – for example, b = 6 cm . Multiply these two values: A = 5 cm × 6 cm = 30 cm² .
What is the relation between area of rectangle and perimeter of rectangle?What is the formula for area and perimeter of rectangle? The formula for area of rectangle is product of length and breadth and the perimeter formula for rectangle is twice of (length + breadth).
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Areas of rectangles with the same perimeter calculator
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